gibsonj338

First take $17.60 and divide it by the number of slices to get what each slice costs.

$17.60/16 = $1.10

Multiply the cost of one slice by the number of slices eaten

$1.10 x 6 = $6.60

Brad ate $6.60 of the pizza.

This may be the right answer; however, the instructions say to use logarithmic differentation.  If anyone knows how to solve for the answer usin logarithmic differentation, I would really appreciate it.  Thanks.

Whoops.  I forgot to put to the third power on (t^4-1).  The equation should be h(t)=(t^4-1)^3(t^3+1)^4.  Can you please do it again?  I am so sorry.

Thanks for the help.  I way over thought this problem. y=mx+b makes total sense.  I feel really dumb.  Now I can finish my homework.  I do know how to use Desmos.

Huh?  What kind of an answer is that?  If you do not know the answer to these questions, then do not answer.

$x+\frac{5}{x}-1+x+\frac{8}{x}+1=8x+\frac{9}{{x}^{2}}-1$

$2x+\frac{5}{x}-1+\frac{8}{x}+1=8x+\frac{9}{{x}^{2}}-1$

$2x+\frac{5}{x}-0+\frac{8}{x}=8x+\frac{9}{{x}^{2}}-1$

$2x+\frac{5}{x}+\frac{8}{x}=8x+\frac{9}{{x}^{2}}-1$

$2x+\frac{13}{x}=8x+\frac{9}{{x}^{2}}-1$

$2x+\frac{13}{x}-8x=8x+\frac{9}{{x}^{2}}-1-8x$

$-6x+\frac{13}{x}=8x+\frac{9}{{x}^{2}}-1-8x$

$-6x+\frac{13}{x}=\frac{9}{{x}^{2}}-1-0x$

$-6x+\frac{13}{x}=\frac{9}{{x}^{2}}-1-0$

$-6x+\frac{13}{x}=\frac{9}{{x}^{2}}-1$

$-6x+\frac{13}{x}-\frac{9}{{x}^{2}}=\frac{9}{{x}^{2}}-1-\frac{9}{{x}^{2}}$

$-6x+\frac{13}{x}-\frac{9}{{x}^{2}}=\frac{0}{{x}^{2}}-1$

$-6x+\frac{13}{x}-\frac{9}{{x}^{2}}=0-1$

$-6x+\frac{13}{x}-\frac{9}{{x}^{2}}=-1$

$-6x+\frac{13}{x}-\frac{9}{{x}^{2}}+1=-1+1$

$-6x+\frac{13}{x}-\frac{9}{{x}^{2}}+1=0$

${x}^{2}(-6x+\frac{13}{x}-\frac{9}{{x}^{2}}+1)=0\times{x}^{2}$

$-6{x}^{3}+\frac{13{x}^{2}}{x}-\frac{9{x}^{2}}{{x}^{2}}+1{x}^{2}=0\times{x}^{2}$

$-6{x}^{3}+13x-\frac{9{x}^{2}}{{x}^{2}}+1{x}^{2}=0\times{x}^{2}$

$-6{x}^{3}+13x-9+1{x}^{2}=0\times{x}^{2}$

$-6{x}^{3}+13x-9+{x}^{2}=0\times{x}^{2}$

$-6{x}^{3}+13x-9+{x}^{2}=0$

$-6{x}^{3}+{x}^{2}+13x-9=0$

Since you cannot factor any further, the only way I know of to finish solving this equation is by graphing.

${2}^{5}\times{4}^{\frac{1}{2}}$

$2\times2\times2\times2\times2\times\sqrt{{4}^{1}}$

$4\times2\times2\times2\times\sqrt{{4}^{1}}$

$8\times2\times2\times\sqrt{{4}^{1}}$

$16\times2\times\sqrt{{4}^{1}}$

$32\times\sqrt{{4}^{1}}$

$32\times\sqrt{4}$

$32\times2$

$64$

Let x = phone's original price

Let 0.2 (20%) = discount of phone

Let 640 = price of phone after discount

$0.2x=x-640$

$0.2x-x=x-640-x$

$-0.8x=x-640-x$

$-0.8x=-640-0$

$-0.8x=-640$

$\frac{-0.8x}{-0.8}=\frac{-640}{-0.8}$

$1x=\frac{-640}{-0.8}$

$x=\frac{-640}{-0.8}$

$x=800$

$59={17}^{x}$

${log}_{17}59=x$

$x=\frac{log59}{log17}$

$x≈1.4391918111143888$

$y=(x+h)2$

$y=2(x+h)$

$y=2x+2h$

First find a point on the graph and replace $x$ and $y$ for the point.  The point I will use is the point $(2,0)$

$y=2x+2h$

$0=2(2)+2h$

Next solve for $h$.

$0=2(2)+2h$

$0=4+2h$

$0-4=4+2h-4$

$-4=4+2h-4$

$-4=2h-0$

$-4=2h$

$\frac{-4}{2}=\frac{2h}{2}$

$-\frac{4}{2}=\frac{2h}{2}$

$-\frac{2}{1}=\frac{2h}{2}$

$-2=\frac{2h}{2}$

$-2=\frac{1h}{1}$

$-2=1h$

$-2=h$

$h=-2$

The answer is $h=-2$.  The equation is $y=2(x+(-2))$ or $y=2(x-2)$ or $y=2x-4$

$(x-9)({x}^{7}+{x}^{6}+{x}^{5}+{x}^{4}+{x}^{3}+{x}^{2}+x+1)$

${x}^{8}+{x}^{7}+{x}^{6}+{x}^{5}+{x}^{4}+{x}^{3}+{x}^{2}+1x-9{x}^{7}-9{x}^{6}-9{x}^{5}-9{x}^{4}-9{x}^{3}-9{x}^{2}-9x-9$

${x}^{8}-8{x}^{7}-8{x}^{6}-8{x}^{5}-8{x}^{4}-8{x}^{3}-8{x}^{2}-8x-9$

Actually the answer is 899.9.