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avatar+1904 

Estimate the instantaneous rate of change for the function f(x)=e^x at x=0, then use this to find an equation for the tangent line.  Check your answer by graphing the function and it's tangent line in Desmos.  Print out and attach a copy of your graph.

 

I have a worksheet in my calculus class due on Monday, April 9, 2018 and need help with this question.  Anyone who knows the answer and can show step-by-step instructions, I would really appreciate it.  Thanks.

 Apr 9, 2018
 #1
avatar+107030 
+1

Estimate the instantaneous rate of change for the function f(x)=e^x at x=0, then use this to find an equation for the tangent line.  Check your answer by graphing the function and it's tangent line in Desmos.  Print out and attach a copy of your graph.

 

f(x)=e^x

f'(x)=e^x

f'(0)=e^0=1

 

So the instantaneous rate of change at x=0 is 1, this is also the gradient of the tangent to the curve at x=0 as that is what the instantaneous rate of change IS

 

When x=0

f(0) = e^0 = 1

so what is the equation of the line through (0,1) with a gradient of 1

 

y=mx+b

y=1x+1

y=x+1

 

You can do the desmos graph I expect :)

 Apr 9, 2018
 #3
avatar+1904 
0

Thanks for the help.  I way over thought this problem. y=mx+b makes total sense.  I feel really dumb.  Now I can finish my homework.  I do know how to use Desmos.

gibsonj338  Apr 9, 2018
 #2
avatar+11129 
+1

Estimate the instantaneous rate of change for the function f(x)=e^x at x=0, then use this to find an equation for the tangent line.  Check your answer by graphing the function and it's tangent line in Desmos.  Print out and attach a copy of your graph.


laugh

 Apr 9, 2018

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