Consider the curve defined by \(y = x + \frac{{x}^{2}}{2}\) over the interval [0, 3].

a) Write (and simplify) a Riemann sum with n subintervals to approximate the area of the region between the curve and the x-asix over this interval. You may use either Right Hand Rule or Left Hand Rule. Note: your final expression should only involve the unknown n.

b) Take the linit of your expression as \(n \rightarrow ∞\). Give a conclusion that clearly states what this limit represents as a definite integral.

Anyone who know how to answer this question and can give step by step instructions, I would really appreciate it. Thanks.

gibsonj338 Feb 4, 2019

#1**+4 **

\(\text{using }n \text{ subintervals we get}\\ x_k = \dfrac{(3-0)k}{n} = \dfrac{3k}{n}\\ \Delta = x_1- x_0 = \dfrac 3 n\)

\(\text{the left hand Riemann sum is} \\ \dfrac 3 n\sum \limits_{k=0}^{n-1}~\dfrac{3k}{n} + \dfrac{9k^2}{2n^2} = \dfrac{9}{4 n^2}-\dfrac{45}{4 n}+9\\ \text{you need to show this last equality of course}\)

\(\text{Pretty clearly}\\ \lim \limits_{n\to \infty}~\dfrac{9}{4n^2}-\dfrac{45}{4n} + 9 = 9\\ \text{which is the value of the definite integral of }y \text{ over }[0,3]\)

.Rom Feb 5, 2019