gibsonj338

In algebra, a polynomial is an expression consisting of the sum of two or more terms each of which is the product of a constant and a variable raised to an integral power: ax²+bx+c is a polynomial, where a,b, and c, are constants and x is the variable.  A simular expression in one than one variable, as 4x²y³-3xy+5x+7. 

\(-4.3<-2.91\)

                                              24

                                            /      \

                                          2       12

                                                  /     \

                                                 2      6

                                                        /   \

                                                      2     3

\({2}^{3}\times3\)

\(8\times3\)

\(24\)

What Coldplay said is correct, but just in case you still do not understand.  I will show several examples.

If the dominators of the two fractions are different, you have to make the dominators the same and then subtract the two fractions.

\(\frac{2}{3}-\frac{3}{5}\)

\(\frac{10}{15}-\frac{9}{15}\)

\(\frac{1}{15}\)

If the dominators of the two fractions are the same, leave the dominators alone and subtract the two fractions.

\(\frac{2}{3}-\frac{1}{3}\)

\(\frac{1}{3}\)

This will even work with adding fractions togother.

If the dominators of the two fractions are different, you have to make the dominators the same and then add the two fractions.

\(\frac{2}{3}+\frac{3}{5}\)

\(\frac{10}{15}+\frac{9}{15}\)

\(\frac{19}{15}\) or \(1\frac{4}{15}\)

If the dominators of the two fractions are the same, leave the dominators alone and add the two fractions.

\(\frac{2}{3}+\frac{1}{3}\)

\(\frac{3}{3}\) or \(1\)

There are three ways to calculate the area of a rhombus:

1. Multiply the lengths of the rhombus' two diaginals togother and then divide the result by two.
2. Multiply the base and the height of the rhombus together.
3. Use Trignometry,  Take the length of any side  of the rhombus and square it then multiple the result by the sine of one of the angles of the rhombus.

I agree; however, what does this have to do with math?

Think of the whoe number as a fraction.  The whole number is the numerator and the dominator is 1.  Then multiply the numerators togother and multiply the dominators togother.  Then if possible, reduce the fraction.

Example:

\(5\times\frac{2}{3}\)

\(\frac{5}{1}\times\frac{2}{3}\)

In Improper form: \(\frac{10}{3}\)

In mixed form:  \(3\frac{1}{3}\)

In decimal form: \(3.3333333...\)

\(-3.4444444...\), \(-3.42222222...\), \(({\frac{1}{3}})^{-2}\), \(\frac{2}{5}\)  In order from greatest to least.

\(({\frac{1}{3}})^{-2}\)

\(\frac{1}{({\frac{1}{3})}^{2}}\)

\(\frac{1}{\frac{1}{9}}\)

\(\frac{\frac{9}{1}}{1}\)

\(\frac{9}{1}\)

\(9\)

-----------------------

\(\frac{2}{5}\)

\(0.4\)

The order from highest to lowest is: \(({\frac{1}{3}})^{-2}\), \(\frac{2}{5}\), \(-3.42222222...\), \(-3.4444444...\)

\(({\frac{2}{3}})^{-3}\)

\(\frac{1}{({\frac{2}{3})}^{3}}\)

\(\frac{1}{\frac{8}{27}}\)

\(\frac{\frac{27}{8}}{1}\)

\(\frac{27}{8}\)

     \(4:00\)

\(-\) \(3:06\)

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      \(3:60\)

\(-\)  \(3:06\)

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     \(3:5(10)\)

\(-\) \(3:06\)

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     \(0:54\)