Member: gibsonj338

If you mean $\sqrt{x-y}$, you cannot seperate $x$ and $y$ into $\sqrt{x}-\sqrt{y}$. If $x$ and $y$ was $\sqrt{x\times y}$, then you can seperate $x$ and $y$ into $\sqrt{x}\times\sqrt{y}$. If $x$ and $y$ was $\sqrt\frac{{x}}{y}$, then you an seperate $x$ and $y$ into $\frac{{\sqrt x}}{\sqrt y}$. If you mean $\sqrt{x}-y$, you cannot add a $\sqrt{}$ to y, that would change the problem entirely.

Example:

Let $x=3$ and let $y=2$

$\sqrt{x-y}$

$\sqrt{3-2}$

$\sqrt{1}$

$1$

The answer is $1$

Now lets do $\sqrt{x}-\sqrt{y}$

Let $x=3$ and let $y=2$

$\sqrt{x}-\sqrt{y}$

$\sqrt{3}-\sqrt{2}$

$1.7320508075688773...-1.414213562373095...$

$0.3178372451957823...$

The answer is $0.3178372451957823...$

$1$ and $0.3178372451957823...$ are not the same answer.

Now lets do $\sqrt{x\times y}$

Let $x=3$ and let $y=2$

$\sqrt{x\times y}$

$\sqrt{3\times 2}$

$\sqrt{6}$

$2.4494897427831781...$

The answer is $2.4494897427831781...$

Now lets do $\sqrt{x}\times\sqrt{y}$

Let $x=3$ and let $y=2$

$\sqrt{x}\times\sqrt{y}$

^{$\sqrt{3}\times\sqrt{2}$}

^{$1.7320508075688773... \times 1.414213562373095...$}

$2.4494897427831781...$

The answer is $2.4494897427831781...$

$2.4494897427831781...$ and $2.4494897427831781...$ are the same answer.

Now lets do $\sqrt\frac{{x}}{y}$

Let $x=3$ and let $y=2$

$\sqrt\frac{{x}}{y}$

$\sqrt\frac{{3}}{2}$

$1.224744871391589...$

The answer is $1.224744871391589...$

Now lets do $\frac{{\sqrt x}}{\sqrt y}$

Let $x=3$ and let $y=2$

$\frac{{\sqrt x}}{\sqrt y}$

$\frac{{\sqrt 3}}{\sqrt 2}$

$\frac{1.7320508075688773...}{1.414213562373095...}$

$1.224744871391589...$

The answer is $1.224744871391589...$

$1.224744871391589...$ and $1.224744871391589...$ is the same answer

Now lets do $\sqrt{x}-y$

Let $x=3$ and let $y=2$

$\sqrt{x}-y$

$\sqrt{3}-2$

$1.7320508075688773...-2$

$-0.2679491924311227...$

The answer is $-0.2679491924311227...$

Now let do $\sqrt{x}-\sqrt y$

Let $x=3$ and let $y=2$

$\sqrt{x}-\sqrt y$

$\sqrt{3}-\sqrt 2$

$1.7320508075688773...-1.414213562373095...$

$0.3178372451957823...$

The answer is $0.3178372451957823...$

$-0.2679491924311227...$ and $0.3178372451957823...$ are not the same answer

Hope this helps

gibsonj338Jan 12, 2016

+1904

$2x\times6x\times101+1=12\times x102x\times333+516-25$

$12x{}^{2}\times101+1=12\times x102x\times333+516-25$

$1212x{}^{2}+1=12\times x102x\times333+516-25$

$1212x{}^{2}+1=12\times 102x{}^{2}\times333+516-25$

$1212x{}^{2}+1=1224x{}^{2}\times333+516-25$

$1212x{}^{2}+1=40592x{}^{2}+516-25$

$1212x{}^{2}+1=40592x{}^{2}+491$

$1=39380x{}^{2}+491$

$-490=39380x{}^{2}$

$\frac{-490}{39380}=x{}^{2}$

$-\frac{490}{39380}=x{}^{2}$

$x{}^{2}=-\frac{490}{39380}$

$x{}^{2}=-\frac{49}{3938}$

$x≈ 0.1115475880428244i$ or $x≈-0.1115475880428244i$

gibsonj338Jan 12, 2016

+1904

$$520\times10.1=$5252$

$$520-$5252=$-4732$

$$-4732\times0.3=$-1419.60$

$$-4732-$1419.60=$-6151.60$

The sale price after both markdown is $$-6151.60$.

gibsonj338Jan 7, 2016

+1904

$x+14y=84$

$2x-7y=-7$

In the first equation, solve for $x$

$x-14y=84$

add $14y$ to both sides

$x=84+14y$

Now subsitute $84+14y$ in the second equation where you see x

$2(84+14y)-7y=-7$

Distribute the $2$

$168+28y-7y=-7$

Now add $28y$ and $-7$ together

$168+21y=-7$

Now subtract $168$ from both sides

$21y=-175$

Now divide $21$ to both sides

$y=\frac{-25}{3}$

$y=-\frac{25}{3}$

In decimal form

$y=-8.333333...$

gibsonj338Jan 7, 2016

+1904

$-y≥x+1$

$y≤\frac{x+1}{-1}$

$y≤-\frac{x+1}{1}$

$y≤-(x+1)$

$y≤-x-1$

This is what the graph looks lile: https://www.desmos.com/calculator/5b51b1qtdj

gibsonj338Jan 7, 2016

+1904

+10

If you mean answer in fraction form:

${10}^{5}$

$100,000$

$\frac{100,000}{1}$

If you mean problem in fraction form:

${10}^{5}$

$\frac{{10}^{5}}{1}$or $\frac{1}{{10}^{-5}}$

gibsonj338Jan 7, 2016

+1904

Alright, I wlll not die. I will give you a moment.

gibsonj338Jan 7, 2016

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