Questions 101
Answers 460


To answer the question, first figure out the equaton of the line. To do that first find the slope.  The formula for the slope of a line is


\(m=\frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}\) where m = slope, \({y}_{2}\) = y-coordinate in the second point, \({y}_{1}\) = y-coordinate in the first point, \({x}_{2}\) = x-coordinate in the second point, and \({x}_{1}\) = x-coordintate in the first point.




m = ?


\({y}_{2}\) = 10


\({y}_{1}\) = -2


\({x}_{2}\) = 5


\({x}_{1}\) = 1














Now that we know that the slope of the line is 3, put that in the equation for a line.  The equation for a line is


\(y=mx+b\) where \(y\) = y-coordinate, \(m\) = slope, \(x\) = x-coordinate, and \(b\) = y intercept (where line crosses the y axis).  Take one of the points and susitute \(x\) and \(y\) in the equation so we can solve for b.




\(y\) = 10


\(m\) = 3


\(x\) = 5


\(b\) = ?
















Now fill in what you know leaving \(y\) and \(x\) as \(y\) and \(x\).




To figure out at which point the line crosses the y-axis, subsitute \(x\) for 0 and solve for \(x\).










The point that the line crosses the y-axis is at point \((0,-5)\) which means that the answer is neither a, b, c, or d.

Aug 24, 2017