We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive pseudonymised information about your use of our website. cookie policy and privacy policy.


Questions 101
Answers 460


To answer the question, first figure out the equaton of the line. To do that first find the slope.  The formula for the slope of a line is


\(m=\frac{{y}_{2}-{y}_{1}}{{x}_{2}-{x}_{1}}\) where m = slope, \({y}_{2}\) = y-coordinate in the second point, \({y}_{1}\) = y-coordinate in the first point, \({x}_{2}\) = x-coordinate in the second point, and \({x}_{1}\) = x-coordintate in the first point.




m = ?


\({y}_{2}\) = 10


\({y}_{1}\) = -2


\({x}_{2}\) = 5


\({x}_{1}\) = 1














Now that we know that the slope of the line is 3, put that in the equation for a line.  The equation for a line is


\(y=mx+b\) where \(y\) = y-coordinate, \(m\) = slope, \(x\) = x-coordinate, and \(b\) = y intercept (where line crosses the y axis).  Take one of the points and susitute \(x\) and \(y\) in the equation so we can solve for b.




\(y\) = 10


\(m\) = 3


\(x\) = 5


\(b\) = ?
















Now fill in what you know leaving \(y\) and \(x\) as \(y\) and \(x\).




To figure out at which point the line crosses the y-axis, subsitute \(x\) for 0 and solve for \(x\).










The point that the line crosses the y-axis is at point \((0,-5)\) which means that the answer is neither a, b, c, or d.

Aug 24, 2017