gibsonj338

Rats.

Any name that starts with an E such as Er (character's name from television show "Aqua Teen Hunger Force"), Elle, Ed, Eddy, Earnie, Esther, Esme, Elanor, Elsie, Evan, Evelyn, Eliza, Eilidh, Elliot, Emilia, Eve, Eden, Elise, Elliott, Ellis, Eloise, Ewan, Edth, Eimear, Elena, Elijah, Elis, Esau, Elisha, etc.

\(28y+6=50\)

\(28y+6-6=50-6\)

\(28y=44\)

\(\frac{28y}{28}=\frac{44}{28}\)

\(y=\frac{44}{28}\)

\(y=\frac{44}{28}\frac{÷}{÷}\frac{4}{4}\)

\(y=11/7\)

\(y≈ 1.5714285714285714\)

\(5xyz=xyz\)

Solve for x.

\(5xyz=xyz\)

\(\frac{5xyz}{yz}=\frac{xyz}{yz}\)

\(5x=x\)

\(5x-x=x-x\)

\(4x=0\)

\(\frac{4x}{4}=\frac{0}{4}\)

\(x=0\)

Solve for y.

\(5xyz=xyz\)

\(\frac{5xyz}{xz}=\frac{xyz}{xz}\)

\(5y=y\)

\(5y-y=y-y\)

\(4y=0\)

\(\frac{4y}{4}=\frac{0}{4}\)

\(y=0\)

Solve for z.

\(5xyz=xyz\)

\(\frac{5xyz}{xy}=\frac{xyz}{xy}\)

\(5z=z\)

\(5z-z=z-z\)

\(4z=0\)

\(\frac{4z}{4}=\frac{0}{4}\)

\(z=0\)

\(x=0\)

\(y=0\)

\(z=0\)

10,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000

a = 19

A = 43°

B = 26°

I know the problem says to find the length of c; however, angle C and length b can also be found using the Law of Sines and that a traingle is equal to 180°.

\(\frac{sin(A)}{a}=\frac{sin(B)}{b}=\frac{sin(C)}{c}\)

To find angle C, subtract angles A and B from 180°.

\(C=180°-43°-26°\)

\(C=137°-26°\)

\(C=111°\)

Now I will find length b.

\(\frac{sin(43°)}{19}=\frac{sin(26°)}{b}\)

\(19b\times\frac{sin(43°)}{19}=19b\times\frac{sin(26°)}{b}\)

\(sin(43°)b=19sin(26°)\)

\(\frac{sin(43°)b}{sin(43°)}=\frac{19sin(26°)}{sin(43°)}\)

\(b=\frac{19sin(26°)}{sin(43°)}\)

\(b≈\frac{19\times0.438371146789}{sin(43°)}\)

\(b≈\frac{8.329051788991}{sin(43°)}\)

\(b≈\frac{8.329051788991}{0.681998360062}\)

\(b≈12.2127152743209113\)

\(b≈12.2\)

Now I will length c.

\(\frac{sin(43°)}{19}=\frac{sin(111°)}{c}\)

\(19c\times\frac{sin(43°)}{19}=19c\times\frac{sin(111°)}{c}\)

\(sin(43°)c=19sin(111°)\)

\(\frac{sin(43°)c}{sin(43°)}=\frac{19sin(111°)}{sin(43°)}\)

\(c=\frac{19sin(111°)}{sin(43°)}\)

\(c≈\frac{19\times0.933580426497}{sin(43°)}\)

\(c≈\frac{17.738028103443}{sin(43°)}\)

\(c≈\frac{17.738028103443}{0.681998360062}\)

\(c≈ 26.0089014023881936\)

\(c≈26.0\)

A = 43°

B = 26°

C = 111°

a = 19

b ≈ 12.2

c ≈ 26.0

To find out how many seconds are in two weeks, first you have to find out how many seconds are in a minute.  1 minute equals 60 seconds.

Next, you have to find out how many minutes equal 1 hour.  1 hour equals 60 minutes.

Since 1 minute equals 60 seconds and 1 hour equals 60 minutes, you can calculate the number of seconds in an hour by multiplying 60 by 60 and when you do that you get 3600 seconds.

Next, you have to find out how many hours are in a day.  1 day equals 24 hours.

Since 1 hour equals 3600 seconds and 1 day equals 24 hours, you can calculate the number of seconds in one day by multiplying 3600 by 24 and when you do that you get 86400 seconds.

Next, you have to find out how many days are in a week,  1 week equals 7 days.

Since 1 day equals 86400 seconds and 1 week equals 7 days, you can calculate the number of seconds in one week by multiplying 86400 by 7 and when you do that you get 604800 seconds.

Next, you have to figure out how many seconds are in 2 weeks.  Since 1 week is equal to 604800 seconds, multiply 804800 by 2 and when you do that you get 1209600 seconds.

2 weeks is equal to 1209600 seconds.

\(\frac{1}{2}\times1000\)

\(\frac{1}{2}\times\frac{1000}{1}\)

\(\frac{1000}{2}\)

\(500\)

\(x+y=13\)

\(x\times y = -30\)

Take the first equation and solve for y.

\(x+y=13\)

\(x+y-x=13-x\)

\(0+y=13-x\)

\(y=13-x\)

Take that equation you solved for y and sbtitute y in the second equation.

\(x\times(13-x)=-30\)

\(13x-x^2=-30\)

\(13x-x^2+30=-30+30\)

\(13x-x^2+30=0\)

\(-x^2+13x+30=0\)

\((-1)\times(-x^2+13x+30)=0\times(-1)\)

\(x^2-13x-30=0\)

\((x-15)(x+2)=0\)

\(x-15=0\)    \(x+2=0\)

\(x-15+15=0+15\)    \(x+2-2=0-2\)

\(x-0=15\)    \(x+0=-2\)

\(x=15\)    \(x=-2\)

Subsitute the two numbers in the two original equations to see if the two answers work.

\(15+(-2)=13\)    \(15\times(-2)=-30\)

\(15-2=13\)    \(15\times(-2)=-30\)

\(13=13\)    \(-30=-30\)

Both numbers checks out which means the two numbers that add up to 13 and multiply to -30 are 15 and -2.

\(sin(x)=-\frac{1}{\sqrt{2}}\)

\({sin}^{-1}(sin(x))={sin}^{-1}(-\frac{1}{\sqrt{2}})\)

\(x=-\frac{\pi}{4}\)

That is how you do it with a calculator.  To get to the answer without using a calculator, looking at the unit circle, what point on the unit circle between \(-\frac{\pi}{2}\) and \(\frac{\pi}{2}\) is the y value equal to \(-\frac{1}{\sqrt{2}}?\)  The point on the unit circle is actually a point that is easily memorized.