Umm, so what do we do?
Nope, thank you for all the help :)
Yep! No need to re-do it, I copied your steps with the correct derivative. Thanks :)
So the Point of Intersection would be: (-17/21,-17/21)
Since the actual slope is -20
23=-20(-2)+b
b=-17
y=-20x-17
Setting them equal to one another
x=-17/21 -- Plugging in to find y
POI = (-17/21,-17/21)Is that correct?
√(1/4) = 1/2 (or 0.5) If you think about it square root of 1 is 1 and the square root of 4 is 2.
0.5/4√1/8 = √2/4
Isn't the derivative of f(x)=5x^2+3 = f'(x)=10x
Okay, but they say the point 2,1 exists. On that graph 2,1 is just put there. Is that allowed?
t^2=324
Take the square root of both sides
t = +/- 18
t = -18, 18
Okay, so this what got me a bit confused:
How can there be -2 seconds in a real-life problem?
10 log (1.8 x 10^12)
= 122. 6
+956 