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A student at Harvard named Kevin
Was counting his stones by 11
He messed up n times
And instead counted 9s
And wound up at 2007.

To be precise, Kevin divides 2007 stones into groups of 9 stones and 11 stones, where n of the groups have 9 stones in them. How many values of  could make this limerick true?

 

(Kevin can mess up every time)

 May 11, 2020
 #1
avatar+463 
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Hi Guest!

 

I have no idea how to solve this, but I think this question has already been answered here: https://web2.0calc.com/questions/a-student-at-harvard-named-kevin-was-counting

 May 11, 2020
 #2
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I got 20 the first time too but it is incorrect and I'm not sure why. Since He can mess up every time would the answer just be 2007/9 = 223?

Guest May 11, 2020

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