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# correction on a previous problem?

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https://web2.0calc.com/questions/let-f-be-the-piecewise-function-such-that-at-how_1

I stumbled upon this problem and I was looking at the solution, but I think the answer is actually 3 points because if you plug in 2 to the second equation, it makes the equation 0 so it also works. I am just asking to see if my understanding is correct or if I missed something, thanks.

May 15, 2020

#1
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hmmm I think CPhill is correct...

If you plug in 2 to the second equation, you get: \(2^2+3(2)-38=4+6-38=\boxed{-28}\)

And \(-28 \neq 2\)

May 15, 2020
#3
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Ah, I see. I definitely mixed some stuff up and was looking at the wrong equation. Sorry for the mixup.

Guest May 15, 2020
#5
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no its ok! i'm glad you learned something!!! :))))

#2
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On this graph: https://www.desmos.com/calculator/c34qmb8s4t

The graph of the function is in red, and the function has a value of  2  at only two points.

(The red function intersects the green line at only two points.)

May 15, 2020
#4
+2

I see. Thanks for graphing it for me.

Guest May 15, 2020