https://web2.0calc.com/questions/let-f-be-the-piecewise-function-such-that-at-how_1
I stumbled upon this problem and I was looking at the solution, but I think the answer is actually 3 points because if you plug in 2 to the second equation, it makes the equation 0 so it also works. I am just asking to see if my understanding is correct or if I missed something, thanks.
hmmm I think CPhill is correct...
If you plug in 2 to the second equation, you get: \(2^2+3(2)-38=4+6-38=\boxed{-28}\)
And \(-28 \neq 2\)
On this graph: https://www.desmos.com/calculator/c34qmb8s4t
The graph of the function is in red, and the function has a value of 2 at only two points.
(The red function intersects the green line at only two points.)