MaxWong
Jun 24, 2019

MaxWong
Jun 24, 2019

MaxWong
Dec 18, 2018

#1**0 **

All the possible events and their probability are as follows:

Event | Prob. |

HH | 1/4 |

HT | 1/4 |

TH | 1/4 |

TT | 1/4 |

There is a probability of 1/4 + 1/4 = 1/2 that the number of runs is 1 and a probability of 1/2 that the number of runs is 2. Hence, the expected number of runs is:

(1/2)(1) + (1/2)(2) = **1.5**.

MaxWongOct 21, 2024