+9673 If D is a point inside triangle ABC, then prove that AB + AC \(\ge\) DB + DC
I know this seems intuitive, but I don't know how to prove it.
+129852 
Let D be any point in the interior of ABC.....draw BD and extend this to E, lying on AC
So.....
DE + EC > DC .... add BD to both sides
(DE + BD) + EC > DC + BD
BE + EC > DC + BD
AB + AE > BE .......add EC to both sides
AB + (AE + EC) > BE + EC
AB + AC > BE +EC which implies that
AB + AC > DC + BD
