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https://web2.0calc.com/questions/please-help_75763

Please help me because this(^) question is already locked.

 Jan 29, 2019
 #1
avatar+101729 
+1

 

https://web2.0calc.com/questions/please-help_75763

 

I've opened it max but I do not know how long it will stay open for. 

 Jan 29, 2019
 #2
avatar+7531 
+1

Thank you Melody :)

MaxWong  Jan 29, 2019
 #3
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+2

Hi Max:  Mathematica 11  gives this and says LHS =RHS but no other explanation. Sorry about that:

 

8 log(Γ(3/4)/Γ(5/4)) - log(1280/81) = 4 log(2) + 4 log(3) - log(5) - 8 log(π) + 16 log(Γ(3/4))

 Jan 29, 2019
 #4
avatar+7531 
+1

Proving the integral to be LHS is more feasible. Thanks for the help, I haven't tried rewriting the right hand side.

MaxWong  Jan 29, 2019
 #5
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+2

I asked it to simplify the RHS and it gave these:
log(1296/5) - 8 log(π) + 16 log(Γ(3/4))
log(331776/5) + 8 (log(π) - 2 log(Γ(1/4)))
-log(5) + 4 log(6) - 8 log(π) + 16 log(Γ(3/4))
= -0.34774389941635582079534116072897304565732004913773310141

 Jan 29, 2019

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