"What is your play titled???......"The Odd Couple???" (well....only one of them really is.....!!!)"
I love it!!! Thanks Chris :))
I think that you should post you play on the forum 7up.
We'd all like to read it. And we, as citizens of Camelot, all make great literary critics too.
What info do you have?
Slope (or gradient) is rise over run.
rise is the difference in the y values and slope is the diference in the x value.
It is a square - so
OA=OC
so why have 2 different pronumerals?
AP and MQ meet at P
I assume that you mean
AC and MQ meet at P ??
Just divide both sides by 8
Thanks Sasini but where is the y solution?
$$\\\frac{7.3*10^3}{ 4.5*10^6}\\\\ =\frac{7.3}{4.5}\times \frac{10^3}{10^6}\\\\ =\frac{7.3}{4.5}\times \frac{10^3}{10^6}\\\\ =1.6\dot2\times \frac{10*10*10}{10*10*10*10*10*10}\\\\ =1.6\dot2\times \frac{1}{10*10*10}\\\\ =1.6\dot2\times \frac{1}{10^3}\\\\ =1.6\dot2\times 10^{-3}\\\\ OR\\\\ =\frac{7.3}{4.5}\times \frac{10^3}{10^6}\\\\ =1.6\dot2\times 10^{3-6}\\\\ =1.6\dot2\times 10^{-3}\\\\$$