Melody

Does anyone know how to get Geogebra to make a right angle with a little box ? 

I have never seen it done but it would be wanted often. 

Thanks Chris, I just wanted to give a visual. 

I have not marked right angles as that took too much space but the intenal intervals are all altitudes (have right angles)

I have not included all the working, just the main steps. 

1)  Equation of EC is      x=5

2)  Gradient of AC = 2

3)  Gradient of  DB = -1/2

4)  Equation of DB       m=-1/2      B(7,3)

      y=(-x+13)/2

5)  On linterval  DB         When x=5     y=4

6)  Intersection of DB and EC is   (5,4)

Orthocentre is (5,4) 

You could check this by finding the equation of AF and checking that (5,4) satisfies this equation.

three thousand

3000

@@ End of Day Wrap   Thurs 12/2/15 Sydney, Australia Time 12:30 am  (Really Fri morn)  ♪ ♫

Good evening all, (Well it is late evening for me anyway) lol

Great answers today from TayJay, CPhill, Heureka, hellokittygirl556, BrittanyJ, GenericUserNameHere, NotTheBestMathMaster, dogeminer,Mahum, Mihail and Jillybean.  Thank you all.

Rosala, I would love to include you but I do not think you made a maths post.

Interest posts:

Fri 13/2/15

Well jillybean, we can interprete these questions however we want I guess. 

thanks TayJay,

You had me going around in circles on that one.  LOL

I am sure that you have caught me once or twice in the past  :)))

And it is highly probable that you will again in the furture.  

Just multiply by 100 and put the percent sign after it.

eg

0.045 = 0.045*100 percent = 4.5%

What is the smallest positive number P such that 10500P is a perfect cube?

10500=105*100=7*3*10^2*5

The smallest possible number is\\

7^2*3^2*2

=49*9*2

$${\mathtt{49}}{\mathtt{\,\times\,}}{\mathtt{9}}{\mathtt{\,\times\,}}{\mathtt{2}} = {\mathtt{882}}$$

the smallest number p can be is 882             Corrections made - Thanks anon :)