Melody

Tues 17/2/15

I'll just factorise it.   

$$\\5(x^2+3)^4(2x)(x-2)^4+(x^2+3)^5(4)(x-2)^3\\\\
10x(x^2+3)^4(x-2)^4+4(x^2+3)^5(x-2)^3\\\\
2(x-2)^3(x^2+3)^4\;\;[5x(x-2)+2(x^2+3)]\\\\
2(x-2)^3(x^2+3)^4\;\;[5x^2-10x+2x^2+6]\\\\
2(x-2)^3(x^2+3)^4\;\;[7x^2-10x+6]\\\\$$

hi,

We are not here to do all your homework for you.

Which one don't you understand ?

I don't understand.  What is a natural position? 

100%-60%=40%

40% of $1.10 = 44c

$${\frac{{\mathtt{40}}}{{\mathtt{100}}}}{\mathtt{\,\times\,}}{\mathtt{1.1}} = {\frac{{\mathtt{11}}}{{\mathtt{25}}}} = {\mathtt{0.44}}$$

I quite likely made a mistake but I got

$$db\left(\frac{5-3w}{8}\right)\;\; dollars$$

Maybe this unit will help?

$$\sqrt{x}-16$$     

This cannot be simplifed,

You logic is good but it is not 9 years so anon will have to adjust the answer a little :)