Melody

Thanks Chris this is a good question.  I am just going to think about it myself for a bit. 

My pencil is a lead pencil so L for the pencil

and my pen is Blue so B for the pen

$$\\64\%\; of\; B=L\\
0.64B=L\\
$divide both sides by 0.64$\\
B=\frac{L}{0.64}=\frac{1}{0.64}\times L = 1.5625L$$

So the blue pen is 156.25% the cost of the lead pencil

In other words the blue pen is 56.25% more expensive than the lead pencil.

Check out this trian.  It goes from Shanghai to the Shanghai airport.

It is the worlds fastest.

It doesn't actually run on the track it is a magnetic leviatation train.

It shows two trains passing each other too but you have to be watching LOL

I have travelled on this train, it was certainly an experience.  :)))

Why is it 1/2 +2/3 Alan ?

Don't worry.  I've got it. :)))

That is a pretty amazing looking number !!!

$${\mathtt{2\,222\,222\,222\,222\,222}}{\mathtt{\,\times\,}}{\mathtt{66\,666\,666\,666\,666\,666}} = {\mathtt{148\,148\,148\,148\,148\,131\,851\,851\,851\,851\,852}}$$

Don't go converting anything - Rustynut is just trying to make it look harder than it really is. :))

SOH-CAH-TOA

you have the adjacent and you want to find the hypotenuse So you need A and H

Must be   CAH

$$\\cos57= \frac{8}{H}\\\\
\frac{cos57}{1}= \frac{8}{H}\\\\
\frac{8}{H}=\frac{cos57}{1} \\\\
$You want the unknown to be on the top$\\\\
\frac{H}{8}=\frac{1}{cos57} \\\\
H=\frac{1}{cos57}\times 8 \\\\
H=\frac{8}{cos57} \\\\
H=8\div cos57 \\\\$$

$${\frac{{\mathtt{8}}}{\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}{\left({\mathtt{57}}^\circ\right)}}} = {\mathtt{14.688\: \!627\: \!670\: \!214\: \!035\: \!6}}$$

try this clip

Some of your question seems to be missing. 

$$\\14000=X(1+0.06/12)^{(8*12)}\\\\
14000=X(1.005)^{96}\\\\
X=14000\div 1.005^{96}$$

$${\frac{{\mathtt{14\,000}}}{{{\mathtt{1.005}}}^{{\mathtt{96}}}}} = {\mathtt{8\,673.334\: \!722\: \!274\: \!609\: \!131\: \!8}}$$

$8673.33

I am sorry but I just don't get this question.

What does

 L1:x=3   mean?     Is it some weird ratio?

Is the distance 3 units, if so then it should be 3 units all the time not just at one point.

To me this question does simply does not make any sense.