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calculate how much would need to be invested at 6% p.a. compounded monthly to accumulate to $14000 in 8 years

 Feb 17, 2015

Best Answer 

 #1
avatar+118724 
+5

$$\\14000=X(1+0.06/12)^{(8*12)}\\\\
14000=X(1.005)^{96}\\\\
X=14000\div 1.005^{96}$$

 

$${\frac{{\mathtt{14\,000}}}{{{\mathtt{1.005}}}^{{\mathtt{96}}}}} = {\mathtt{8\,673.334\: \!722\: \!274\: \!609\: \!131\: \!8}}$$

 

$8673.33

 Feb 17, 2015
 #1
avatar+118724 
+5
Best Answer

$$\\14000=X(1+0.06/12)^{(8*12)}\\\\
14000=X(1.005)^{96}\\\\
X=14000\div 1.005^{96}$$

 

$${\frac{{\mathtt{14\,000}}}{{{\mathtt{1.005}}}^{{\mathtt{96}}}}} = {\mathtt{8\,673.334\: \!722\: \!274\: \!609\: \!131\: \!8}}$$

 

$8673.33

Melody Feb 17, 2015

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