$${\mathtt{881}} \,{mod}\, {\mathtt{21}} = {\mathtt{20}}$$
Theere you go, the remainder is 20
this does not make sense to me.
That is all really good feedback guys. :)
solve for distance
Vo= oms per second
acceleration= 2ms per second per second
and time = 3 sec solve for distance
$$\\s=ut+0.5at^2\\ s=0*3+0.5*2*9\\ s=0+9\\ s=9metres$$
it is easier to multiply both sides by 8 to start with.
Yes.
Most older and internet calcs have an ^ sign
sometimes new calcs have a button that looks like $$x^y$$ that is the same thing.
Good try anon but not quite right
(-2 + k) + 1
= -2 + k + 1
= k + 1 - 2
= k -1
csc=1.25 what is the value of cos
$$\\cosec\theta = \frac{Hyp}{opp}=\frac{5}{4}\\\\ adj=\sqrt{25-16}=\sqrt{9}=3\\\\ cos\theta = \frac{adj}{Hyp}=\frac{3}{5}=0.6\\\\ $ that is if it is in the 1st quad, but it might be in the 2nd quad$\\\\ cos\theta = \pm\;0.6$$
You don't need to use a calc. Just move the decimal point over two places to make the number BIGGER.
or any other inverse