Melody

The pi button is next to the [2nd] button at the top

Thanks Chris and TheMathsStudent

I thought there was some definative way to do this.   

$$\\7Xmod26=1\\\\
\frac{7x}{26}=N+\frac{1}{26} \qquad $Where X and N are both integers$\\\\
7X=26N+1$$

Multiples of 26 are   26,52,78, 104,130, 156, 182,

(Multiples of 26) +1  are   27,53,79, 105,   105 = 7*15

So X=15 works this is one solution

7*15=26(N)+1        N=4

-----------------------------------------------------

$$\left({\mathtt{7}}{\mathtt{\,\times\,}}{\mathtt{15}}\right) {mod} \left({\mathtt{26}}\right) = {\mathtt{1}}$$

That is good   X=15 is the smallest value of X

--------------------------------------------------------

Now I want to find a general solution   

If (7*15) mod 26=1

Then I think

(7*15+26G) mod 26 must also =1

Thinking,  thinking.      :/

This might help

Thanks Chris, these are really interesting questions.  There is much I could learn from your answer  :)

Thanks Jgricus01,

If you want to answer questions like these use the [Calculation eg 1+2=3] button

then you can do the calc straight onto the forum and we can see if it is correct at a glance :)

like this

$${\mathtt{5\,416.68}}{\mathtt{\,\times\,}}{\mathtt{12.5}}{\mathtt{\,-\,}}{\mathtt{5\,416.68}} = {\mathtt{62\,291.82}}$$

I'd just do it like this (this is easier)   :)

$$\\ |4x-3|<8\\\\
-8<4x-3<8\\\\
$add 3 to all 3 'sides'$\\\\
-8+3<4x-3+3<8+3\\\\
-5<4x<11\\\\
\frac{-5}{4}

ok Civonamzuk  :))

I have added this to the Sticky topic "Great answers to Learn From"

If anyone would like to take an interest in organising some of our reference material that would be great.

I am amazed Alan !

I was always taught that the world at large would say

$$1.55*10^4$$     is in Scientific Notation.

BUT the English would say it was in   Standard Form

This was an irritation to me at school because the two terms were used interchangably and like you I thought an ordinary number should be in standard form.

Now you are English and you say you do not know the term Standard Form !! I am amazed !!

I didn't know that Chris.

If the first 2 digits if a new century are not divisable by 4 then it will not be a leap year.

Cool!  Thanks.     

Thanks Alan :)