Melody

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UsernameMelody
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Melody  Feb 11, 2022
 #2
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+10

Thanks for your excellent answer Heureka.

 

I just want to practice this for myself because I keep forgetting it.   

 

http://web2.0calc.com/questions/the-equation-of-the-hyperbola-that-has-a-center-at-1-2-a-focus-at-4-2-and-a-vertex-at-3-2-is-frac-x-c-2-a-2-frac-y#r2

 

The equation of the hyperbola that has a center at (0,0) , a focus at (5 , 0) , and a vertex at (-4 , 0 ) , is

$$\frac{x^2}{A^2}-\frac{y^2}{B^2}=1$$

 

Vertex =( 0 $$\pm$$ A, 0)    So A= 4

 

     $$\\Focus=(0\pm \sqrt{A^2+B^2},0)\\\\
\sqrt{16+B^2}=5\\
4^2+B^2=5^2\\
B=3$$

 

$$\frac{x^2}{4^2}-\frac{y^2}{3^2}=1$$

 

Jun 16, 2015
 #2
avatar+118723 
+5
Jun 16, 2015
 #2
avatar+118723 
+5
Jun 16, 2015