Melody

Such a gorgeous rose Mistress Rosala, and it be sat upon such a beautiful Melody. The Queen be truly overwelmed.

Perhap thine demons really are exorcised ?  Still it would be good if Chiurgeon Tud checked thee out. One cannot be too careful where evil demons are concerned. 

Still for now your pretty head be saved from the chopping block!

The kind thoughts that spring from it be much too valuable to waste!  :))

Oh Rosala. Thou out does thineself. Those cupcakes look divine.!!

A great service you do Squire CaptainMan. Treasonous subjects must indeed be be closely guarded.  :)

Mistress Rosala, you claim you were framed but I believe that those monstrous words came directly from thine mouth. !!

Were thee under a sorcerer's spell at the time?

Perhaps we need the servives of Chiurgeon Tud. He hath the magick of the quadratic. Perhap it will aid in thine cure?

He also hath a sister or a cousin. I can not remember which. But she is a powerful sorceress. Her magick may work even if Tud's doth fail.....

Squire CaptainMan, set forth, summons the Chiugeon. Bring him before the Queen. Mistress Rosala must be freed of her evil demons!

That is an excellent answer Mistress Rosala.

This be the first of the bountiful tribute that must be placed at the Queens feet.  

A word of explanation here. Rosala has recently been been accused of treason.

The Queen must be appeased.

Mistress Rosala.

I hear treasonous whispers within Camelot's divine walls!

In 20 years the Queen may be feeble of mind or body but feeble she is not now!!!

You, Mistress Rosala, will lose you head before such time if such treasonous talk continues to reach the Queen's ears!!!

The Queen is greatly angered!!!!

Perhaps the Queen could be mollified with bountiful gifts?

She feels quite petulant at the present time.  There hath nor been a beheading for some time in Camelot. Perhaps not since Sir CPhill lost his head.  The Queen is bored.  A good beheading would offer some entertainment. ://

A) is 1,  just like Alan said.

if all the 20 divisors are the first 20 powers of 2 there will be one prime divisor (That is 2).  This number would be 2^19

Any prime to the power of 19 would work just as well I think.

I do not have a pen and paper or a computer. I just have my phone. So I am going to put down my rambling thoughts.

B) Let me think.....

1×2      2factors

1 x2x3.    3+2c2=4factors

1x2x3x5.  4+3c2+3C1=4+3+1=8factors

1×2×3×5×7=

5+4C2+4C3+4C4

=5+6+4+1=16factors

mmm I can't use any more primes....there would be too many factors. 

So maybe 4 primes is the most? .....

1×2×3×5×7×2

How many factors does this have?

All the 16 from before plus 12,20,28,60,84,140,420

That makes 16+7=23 factors

thats to many. :(

maybe 3 primes is the mosts.

At this point in time I really need a pen and paper and/or computer and some combinatory mathematics.

But do you get where I am going here?

Like I said.  I am really just thinking out loud. There can not be many primes. :(

Nope

no graph. 

3*5=15

1*15=15

0.5*30=15

Where do you want the brackets to go?

Thanks Squareroot,

I am sure that Bertie and Nauseated will both be very pleased about your professor's assessment as well as pleased about your acknowledgement of their skill and your 'thank you' . 

I am glad you enjoy these Squareroot.  I am also a fan of the newer Dr Who series.

The original series were from 1963 to 1989.  

They were somewhat more basic than the recent series are.