Our guests answer is good but I will just show you how to do it formally,
Let the first number be x
and the next even number will be x+2
x(x+2)=168
x^2+2x-168=0
I want two numbers that multiply to -168 and add to 2
Since they multiply to a negative, one has to be neg and one pos
Since they add to a pos the 'biggest' one is positive
factor(168) = (2^3*3)*7
168=2*2*2*3*7 = (2*2*3)*(2*7) = 12*14
so the numbers are 14 and -12
(x+14)(x-12)=0
x=-14 or 12
so the integers are -14 and -12
or
12 and 14
just like our guest already said. :)