The product of two consecutive even integers is 168. Find the integers.
The positive set of correct answer is___.
(use a comma t separate answers as needed.)
The negative set of correct answer is___.
(use a comma to seperate answers as needed)
Thank You :)
+118724
Our guests answer is good but I will just show you how to do it formally,
Let the first number be x
and the next even number will be x+2
x(x+2)=168
x^2+2x-168=0
I want two numbers that multiply to -168 and add to 2
Since they multiply to a negative, one has to be neg and one pos
Since they add to a pos the 'biggest' one is positive
factor(168) = (2^3*3)*7
168=2*2*2*3*7 = (2*2*3)*(2*7) = 12*14
so the numbers are 14 and -12
(x+14)(x-12)=0
x=-14 or 12
so the integers are -14 and -12
or
12 and 14
just like our guest already said. :)
The product of two consecutive even integers is 168. Find the integers.
The positive set of correct answer is_12, 14__.
(use a comma t separate answers as needed.)
The negative set of correct answer is -12, -14_.
(use a comma to seperate answers as needed)
Welcome.
+118724
Our guests answer is good but I will just show you how to do it formally,
Let the first number be x
and the next even number will be x+2
x(x+2)=168
x^2+2x-168=0
I want two numbers that multiply to -168 and add to 2
Since they multiply to a negative, one has to be neg and one pos
Since they add to a pos the 'biggest' one is positive
factor(168) = (2^3*3)*7
168=2*2*2*3*7 = (2*2*3)*(2*7) = 12*14
so the numbers are 14 and -12
(x+14)(x-12)=0
x=-14 or 12
so the integers are -14 and -12
or
12 and 14
just like our guest already said. :)
