Melody

Beats me, what is the longest word Chris ??

Thanks Heureka,

I understand but it is still really weird.  I will muck around with it some more.

I would just have broken them into their prime factors.

I suppose your way is quicker.... I will have to think about it. ........

My way

90=10*9=2*5*3*3

210=10*21=2*5*3*7

so GCF=2*5*3 =30

Find the LCM of 3x^2,21xy,and 147y^2.

 3x^2           21xy               147y^2.

3xx             3*7xy              3*7*7yy

LCM= 3*7*7*xxyy = 147x²y²

I do not get what you have done Heureka   

ok no worries,

Do not forget to thank heureka :)

It is best to do it on the forum so everyone can see your good manners :)

BrainFreeze,

Are you even looking at the answers that you have already been given?

You have been logged on for hours but you have not responded to any of the answerers who have already tried to help you.

Maybe you can be more polite this time and show an interest in the answer that Heureka has prepared especially for you.

I just had a quick look at that site our guest sent you to.

It looks quite good for checking answers.

I doubt that it explains the answers, although I did not actually use it so I could be wrong.

But sites for checking answers can be very useful too :)

Thanks guest #1

Find the vertex, focus, and directrix equation of y = x2 – 6x – 8.

You need to get your equation in the form  \((x-h)^2=4a(y-k)^2\)

where (h,k) is the vertex and a is the focal length.

Now I can see straight of that this is a concave up parabola.

That is helpful because that tell me that the focus is above the vertex and the directrix is below it.

\(y=x^2-6x-8\\ x^2-6x=y+8\\ \mbox{Now complete the square}\\ x^2-6x+9=y+8+9\\ (x-3)^2=y+17\\ (x-3)^2=4*\frac{1}{4}(y+17)\\ so\\ Vertex=(3,-17)\\ focal \;length = 0.25\\ focus: x=3, y=-17+0.25=-16.75\qquad (3,-16.75)\\ directrix: y=-17-0.25 = -17.25 \qquad y=-17.25\\ \)

Here is the graph

https://www.desmos.com/calculator/yylyzk2bdj

That is not helpful guest.

If you have time to write all that then you have time to do a quick internet search and send our guest to a net page that might be helpful.

OR you culd even just suggest this and give them a sensible word search suggestion like.

"How do I subtract vectors"  There are bound to be some great you tubes on it :)

I am really rusty on vectors - you'll have to wait for someone else :(