Melody

I am just requesting that you smile and say please ;)

Would you like me to give you the correct answer ?

Just smile and say please.  ;)

Why :/  ??

An item that was selling for 72$ is reduced to 60$. Find the percent decrease in price. Round your answer to the nearest tenth. Please show as much work as possible

12/72*100 %

16.6666666666666667 = 16.6666666666666667

16.7%

Two cyclists, k km apart, and starting at the same time, would be together in r hours if they travelled in  the same direction, but would pass each other in t hours if they travelled in opposite directions. The ratio of the speed of the faster cyclist to that of the slower is11:19 AM

do this if you call yourself  master of maths

I do not call myself anything except for Melody.  Your 'challenge' sounds a little impolite but your question is interesting.

What is 11:19 AM ???

What am I meant to be finding ???   I have found the ratio of the speeds.

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Let x be the speed of the faster one    and    let y be the speed of the slower one.    Find x/y

Let the faster one be a 0 on the number line and let the slower one be at +k on the number line.

As they approach each other:

x km/hour = xt km in t hours

y km/hour = yt km in t hours 

xt+yt=k

(x+y)t=k

AS they  move in the same direction.  Both towards th poitive end of the number line

x km/hour = xr km in r hours

y km/hour = yr km in r hours  NEW position will be k+yr

\(k+yr-xr=0\\ xr-yr=k\\ r(x-y)=k\\ so \\ (x+y)t=(x-y)r\\ xt+yt=xr-yr\\ yt+yr=xr-xt\\ y(t+r)=x(r-t)\\ \frac{r+t}{r-t}=\frac{x}{y}\\ \frac{x}{y}=\frac{r+t}{r-t}\)

negative :)

Cool pic :)

\(x^2-x\\=x*x-x*1\\=x(x-1)\)

How to solve: 8(10)^x+2=26

First I subtracted 2 from boths sides to get: 8(10)^x=24   good

Then I divided both sides by 8 getting (10)^x=3               good

I don't know what do do after this part.

When the unknown is a power you usually have  to use logs

\((10)^x=3 \\~\\ log(10)^x=log3 \\~\\ xlog(10)=log3\qquad \qquad \mbox{log10=1 when the base is 10} \\~\\ x*1=log3\qquad \\~\\ x=log_{10}3\\~\\ x\approx 0.4771\)

how do you figure out the scale factor of a dilated figure from its original figure?

If a 2 cm side dilates to 6cm then the scale factor will be 6/2 = 3

Does that answer your question ?

scale factor = new length / original length

How do you find beta and theta

Did you look under the bed?

I find that most things can be found under a bed  !!