How do you find the exact answer to this problem? sin(90°-acsc(3))
Lets see.....
\(sin(90°-acsc(3))\\ sin(90°-asin(\frac{1}{3}))\\\)
Remember that asin or inverse sin of a ratio is an ANGLE so we have
\(sin(90-\theta)=cos\theta\)
\(sin(90°-asin(\frac{1}{3}))\\ =cos(asin(\frac{1}{3}))\\ =\frac{2\sqrt2}{3}\\ \)
check:
sin(90-acsc(3)) = 0.942809041582
2*sqrt(2)/3 = 0.9428090415820634