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How do you find the exact answer to this problem? sin(90°-acsc(3))

Thank you!

 Feb 3, 2019
edited by Guest  Feb 3, 2019
 #1
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How do you find the exact answer to this problem? sin(90°-acsc(3))

 

Lets see.....

\(sin(90°-acsc(3))\\ sin(90°-asin(\frac{1}{3}))\\\)

 

 

Remember that asin or inverse sin of a ratio is an ANGLE so we have

\(sin(90-\theta)=cos\theta\)

 

\(sin(90°-asin(\frac{1}{3}))\\ =cos(asin(\frac{1}{3}))\\ =\frac{2\sqrt2}{3}\\ \)

 

 

 

check:

sin(90-acsc(3)) = 0.942809041582

2*sqrt(2)/3 = 0.9428090415820634

 Feb 3, 2019

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