Melody

Here is one answer

Do you have, or can you find the address of where this was asked last time?

It really is polite to continue it on the original thread, and it is also better for future people who might find it in a search.

Hi ilorty,   

It is in raw form, and I would not normally answer.

But so many people have said that the code does not always render properly these days that I gave them the benefit of the large doubt.

I probably should not have, I think it is only guest posts that have had this problem.

If possible get some blocks and use them to answer the question

How many blocks altogether  3*3*3=27  (you are told that anyway)

1. What is the max number of sides that can be painted on any individual little block?

2. How many in the middle with no paint?

3. Which ones have 3 sides painted?  How many are there?

4. How many have only one side painted, where are those ones?

5. How many blocks have been accounted for so far?

5. The rest must have 2 sides pained, how many is that?

Now answer the question.

Please allow original guest to answer these questions. 

\(x=0.75y\\ \frac{2x+y}{3x-2y}\\ =\frac{1.5y+y}{3*0.75y-2y}\\ =\frac{2.5y}{2.25y-2y}\\ =\frac{2.5y}{0.25y}\\ =\frac{2.5}{0.25}\\ =10 \)

-4*-2.3*23

-4*-2.3*23 = 211.6

what are you talking about?

I do not think that this is possible.

Are you sure your question is copied properly?

Please just post one question per post.

Question 1

I've started it for you.

Now just use angle sum of triangles to find the angles at P and T

Hint:

A radius and a tangent meet at right angles.

35^1723-16^1723

\(35^{1723}-16^{1723}\;\;(mod \;6)\\ =(-1)^{1723}-(-2)^{1723}\;\;(mod \;6)\\ =-1--(2)^{1723}\;\;(mod \;6)\\ =-1+2\;\;(mod \;6)\qquad \text{(2 to the power of any odd interger, mod 6, is 2)}\\ =1 \;\;(mod\; 6) \)