Melody

Antilog(x)=10^x     

60 minutes in an hour

60 seconds in every one of those minutes

so

60*60= 3600 seconds in an hour.

Thank you Maddie that was a really good answer.

Welcome to Web2.0calc forum!

Just remember to give the units.  

There were no units given in the question so the best you can do is unit^2.

okay,

Thank you for telling us that you didn't understand - We need your honest feed  back.  Just make sure you think really hard first.  But if you still don't understand - Always say so.

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CPhill's answer is very good but I will try and break it down further.

First look at the whole trip.

6 hours at 116km/hr   will take the car 6*116 = 696km

So the whole trip is 696km and will take 6 hours.

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Now I am going to look at the first part of the trip.

You travel 262km at a speed of 131km/hour

It will help if you understand that 131km/1hour is the same as 1hour/131km

That is if you go 131km in an hour then you must take 1 hour to travel 131km.

I want to know how long this part of the journey took.

$$\frac{1hour}{131km}\times\frac{262km}{1}$$

the km cancel out and you are left with     $$\frac{262}{131}hours=2 hours$$

So for this first stretch you travel 262km in 2 hours

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Now you need to know the average speed for the second part of the trip.

speed = distance/time

So you need  distance and time taken.

The whole trip took 6 hours.  The first part took 2 hours.  So the second part must have taketn 6-2=4 ours

I worked out that the whole distance was 696km.  The first part was 262km.  So the second part has to be 696-262=434km

Speed for the second part is 434km/4hours = 108.5Km/hour

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I hope that that helps.

Can you explain a little better.  I don't understand.

$$a=\frac{k}{t^2}\\\\
\mbox{ When } t=20\quad a=5m/s^2\quad \mbox{ Find k}\\\\
5=\frac{k}{400}\\\\
k=2000\\\\
so\\\\
a=\frac{2000}{t^2}\\\\
When\quad t=25\\\\
a=\frac{2000}{25^2}\\\\
a=\frac{2000}{625}\\\\
accel=3.2m/s^2$$

Look in the Sticky Topics at the bottom right of your page.

There is one there called "Hoe do I type in fractions"

Look there  

               This is it folks                                

                       $$\textcolor[rgb]{1,0,0}{1}$$

An easy way for a question like this is to draw up a grid like this one.

You can see that there are 6*6=36  Possibilities 

Colour the ones that fit your needs.  

I've done it wrong, you don't need the sum!  

Nevermind I don't need to do another one and I don't have time.

You need all those where both die are less than 4.

That would be the top right hand corner.  9/36 = 1/4

No it is not Zegroes,

His thumb is worth 5 points - these a 1 point downs.  Someone is not being nice!