x2 > 2(x + 4)
You can also do a question like this graphically - which is what I would normally do.
$$x^2>2x+8\\\\
x^2-2x-8>0\\\\
\mbox{You can think of it like this. }\\\\
x^2-2x-8=y \mbox{ Where y is positive}\\\\
y=(x-4)(x+2)\mbox{ Where y is positive}\\\\$$
y=0 when x-4=0 that is when x=4 and also whatn x+2=0 that is when x=-2
So the two roots are x=4 and x=-2.
This is a concave up parabola because the number in front of the x2 is +1 (the + indicates concave up)
Do a very quick sketch - you don't need a vertex or any other features.
I'll do a good sketch because with the computer graphing programs it is too difficult to do a rough one.
You can see from the diagram that y is postive when x>4 and when x<-2
+118725 
