Sasini

(x-2)^2 = (2x-7)^2

x^2-4x + 4 =4x^2 -28x +49

24x -45 =3x^2

3x^2 -24x + 45 =0

x^2 -8x +15 =0

(x -3) (x-5) =0

x -3=0 or x-5 =0

x=3     or  x=5

on that time, x has two answers. so that both them are suitable to value of x

2x^2 - 3y^2 = 5xy

2x^2 -5xy -3y^2 = 0

2x^2 -6xy +1xy -3y^2 =0

2x(x -3y) +y(x-3y) =0

(x-3y)(2x +y) =0

x-3y = 0 or 2x+y =0

x =3y or 2x =-y

              x= -y/2

1 -5(x^3+x^2) = -5x^2 -4(x^3 +2)

1 -5x^3 -5x^2  = -5x^2 -4x^3 -8

1 -5x^3            =  -4x^3 - 8

1 +8                 =   -4x^3  + 5x^3

9                      =      x^3

7 - c = -13

-c     = -13 + 7

-c     =  -6

-c/-1 = -6/-1

 c      = 6//

plz give me those steps. i need them now

$${\mathtt{83}}{\mathtt{\,-\,}}\left[{\mathtt{59}}{\mathtt{\,-\,}}\left({\mathtt{22}}{\mathtt{\,-\,}}{\mathtt{18}}\right)\right]$$

$${\mathtt{83}}{\mathtt{\,-\,}}\left[{\mathtt{59}}{\mathtt{\,-\,}}{\mathtt{4}}\right]$$

$${\mathtt{83}}{\mathtt{\,-\,}}{\mathtt{55}}$$

$${\mathtt{28}}$$

plz solve this problem with the calculator. u can solve it simply

$${\mathtt{\,-\,}}{\mathtt{7}}{\mathtt{\,\times\,}}\left({\mathtt{2}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{1}}\right){\mathtt{\,\small\textbf+\,}}{\mathtt{3}}{\mathtt{\,\times\,}}\left({\mathtt{5}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{4}}\right) = {\mathtt{0}}$$

$${\mathtt{\,-\,}}{\mathtt{14}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{7}}{\mathtt{\,\small\textbf+\,}}{\mathtt{15}}{\mathtt{\,\times\,}}{\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{12}} = {\mathtt{0}}$$

$${\mathtt{x}}{\mathtt{\,-\,}}{\mathtt{19}} = {\mathtt{0}}$$

$${\mathtt{x}} = {\mathtt{19}}$$

I think mathz is the simlest subject in this world

of course dr