how do you solve this quadratic equation? (x-1)^2 = (2x=7)^2
(x - 1)2 = (2x + 7)2
Take square root of both sides. There are two possibilities:
1. x - 1 = 2x + 7 so x = -8
2. x - 1 = -(2x + 7) so x - 1 = -2x - 7 so 3x = -6 so x = -2
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(x-2)^2 = (2x-7)^2
x^2-4x + 4 =4x^2 -28x +49
24x -45 =3x^2
3x^2 -24x + 45 =0
x^2 -8x +15 =0
(x -3) (x-5) =0
x -3=0 or x-5 =0
x=3 or x=5
on that time, x has two answers. so that both them are suitable to value of x
