+0  
 
+5
905
3
avatar+752 

$${\frac{{\mathtt{cotAcosecA}}}{\left({\mathtt{cotA}}{\mathtt{\,\small\textbf+\,}}{\mathtt{cosA}}\right)}} = {\frac{\left({\mathtt{cotA}}{\mathtt{\,-\,}}{\mathtt{cosA}}\right)}{{\mathtt{cotAcosecA}}}}$$

Plz show the first part similar to second part

math
 Aug 19, 2014

Best Answer 

 #4
avatar+118673 
+10

Hi Sasini,

 

EDIT: SORRY I JUST READ WHAT ALAN WROTE.  HE HAS SHOWN THAT THEY ARE NOT EQUAL.

SO YOU WILL HAVE A TOUGH TIME PROVING THAT THEY ARE.  LOL.       (Thanks Alan)

I'D STILL LIKE YOU TO FOLLOW MY ADVICE FOR NEXT TIME  

 

We have done a couple of these for you Sasini.

Here is one we did a day or 2 ago.

 

http://web2.0calc.com/questions/solve-this-gemotery-questions

 

I would like you to attempt this one yourself.

If you get really stuck you can show us what you have tried and we can help you move to the next bit.

You will learn much better if you do this.

You probably should work on the 2 sides seperately and then prove that the LHS=RHS

I usually change everything to sin and cos first but this is not always the best or fastest method.

(It does work though).  You just need a good understanding of simplifying fractions.

Give it a go and try asking specific 'part' questions when you get stuck.  Continue to ask your questions on this thread.  

 Aug 19, 2014
 #2
avatar+752 
+5

first solve the left side hand . bt, it's similar to right side hand

 Aug 19, 2014
 #3
avatar+33661 
+10

The left-hand side is NOT equal to the right-hand side in general.  For example, suppose A = 37°

$${\frac{{cot}{\left({\mathtt{37}}\right)}{\mathtt{\,\times\,}}{csc}{\left({\mathtt{37}}\right)}}{\left({cot}{\left({\mathtt{37}}\right)}{\mathtt{\,\small\textbf+\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}{\left({\mathtt{37}}^\circ\right)}\right)}} = {\mathtt{1.037\: \!348\: \!331\: \!178\: \!024\: \!9}}$$

$${\frac{\left({cot}{\left({\mathtt{37}}\right)}{\mathtt{\,-\,}}\underset{\,\,\,\,^{\textcolor[rgb]{0.66,0.66,0.66}{360^\circ}}}{{cos}}{\left({\mathtt{37}}^\circ\right)}\right)}{\left({cot}{\left({\mathtt{37}}\right)}{\mathtt{\,\times\,}}{csc}{\left({\mathtt{37}}\right)}\right)}} = {\mathtt{0.239\: \!633\: \!701\: \!060\: \!557\: \!7}}$$

 Aug 19, 2014
 #4
avatar+118673 
+10
Best Answer

Hi Sasini,

 

EDIT: SORRY I JUST READ WHAT ALAN WROTE.  HE HAS SHOWN THAT THEY ARE NOT EQUAL.

SO YOU WILL HAVE A TOUGH TIME PROVING THAT THEY ARE.  LOL.       (Thanks Alan)

I'D STILL LIKE YOU TO FOLLOW MY ADVICE FOR NEXT TIME  

 

We have done a couple of these for you Sasini.

Here is one we did a day or 2 ago.

 

http://web2.0calc.com/questions/solve-this-gemotery-questions

 

I would like you to attempt this one yourself.

If you get really stuck you can show us what you have tried and we can help you move to the next bit.

You will learn much better if you do this.

You probably should work on the 2 sides seperately and then prove that the LHS=RHS

I usually change everything to sin and cos first but this is not always the best or fastest method.

(It does work though).  You just need a good understanding of simplifying fractions.

Give it a go and try asking specific 'part' questions when you get stuck.  Continue to ask your questions on this thread.  

Melody Aug 19, 2014

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