Straight

Hello Guest,

There was a total of 20 800 sacks of rice in Factory A and factory B. After 3/4 of

the sacks of rice in Factory A and 3/5 of the sacks of rice in Factory B were sold,

there were 1040 more sacks of rice in Factory b than Factory A. How many sacks

of rice were there in each factory at first?

The nearest possible value is 1040.1: ... 

 ... difference is 1040.1.

I think that is not possible

Straight

Hi Jmaster10,

How about answering questions yourself?

I looked at your profile and I see you only asked questions and didn't answer any.

It's about time. 

What is the point of the solution without perhaps having understood (at least) something yourself (from it)?

Straight

Hello Guest,

Assuming that \(x\neq -5\) , simplify \(\frac{(2x+10)^7}{(x+5)^7}\)

\(\mbox {Factor out 2 from the expression}\)

\(\frac{(2(x+5))^7}{(x+5)^7}\)

\(\mbox {To raise a product to a power, raise each factor to that power}\)

\(\frac{2^7*(x+5)^7}{(x+5)^7}\)

\(\mbox {Reduce the fraction with } (x+5)^7\)

\(2^7=128\)

Hello Guest,

the number is beetween 8 and 6 and that's the number 7:

\(4-x=7\)

\(x=-3\)

\(4+3=7\)

So x is finally -3.

Straight

Hi Guest,

\(9^y=\frac{3^5}{27^3}\)

\(\mbox {Calculate}\)

\(9^y=\frac{243}{19683}\)

\(\mbox {Now divide with 243}\)

\(9^y=\frac{1}{81}\)

\(\mbox {Write the expression in exponential form with the base of 3}\)

\({3}^{2y}=\frac{1}{81}\)

\(\mbox {Write the expression in exponential form with the base of 3}\)

\({3}^{2y}={3}^{-4}\)

\(\mbox {Since the bases are the same, set the exponents equal}\)

\(2y=-4\)

\(\mbox {Divide both sides of the equation by 2}\)

\(y=-2\)

Here's your answer.

 !

Hi Melody,

or using wolframalpha.

THE SOLUTION IS ... 077998673 , so your answer is right.

 !

Hello Guest,

there are 5 solutions, but one of them have positive real numbers.

\((x,y)=(\frac{1}{2},\frac{\sqrt{3}}{2})\) \(\mbox {wolframalpha}\)

\(\frac{1}{2}*\frac{\sqrt{3}}{2}= \mbox { } \approx {0.433}\) .

Straight

Hello Guest,

type in the calculator. \(xy = \mbox{ }\approx {3.7605}\) .

Straight

Hello Guest,

like NaturalDisaster said \(9\frac{4}{15}\) and this amount equals to \(\frac{139}{15}\) .

Straight