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Find the axis of symmetry and the vertex of the graph of f(x) = 2x^2 - 4x.

The axis of symmetry is x= ____, and the vertex is (__,__).

 Apr 13, 2020
 #1
avatar+23689 
+2

-b/2a    will be the x coordinate of the vertex of this bowl shaped parabola

= - -4/4 = 1      x = 1

 

put in x = 1 to find the y value of the vertex

=-2     vertex =   1,-2

 Apr 13, 2020
 #2
avatar+4568 
+1

Your equation is f(x)=2x^2-4x which is a parabola.

 

The axis of symmetry is -b / 2a, when -(-4)/2(2)=4/4=1. x=1 is the line of symmetry.

 

The vertex is 2(1)^2-4(1)=2-4=-2

 

(1,-2)-Vertex.

 Apr 13, 2020

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