a coin is tossed 9 times what is the probability of getting ? a)five heads b)at least two heads
(a): The probability is 9 C 5 / 2^9 = 126 / 512 = 63 / 256....
(b): C(9,0)+C(9,1)=1+9=10.
512-10=502
502/512=251/256.
The probability to get five heads in 9 flips is (1/2)^5 = 1/32 => 4/32=>1/8
