Wow, 1997-1998 and 1998-1999 are very close: 1997-1998: x+some amount, might be larger than the median income in 1998-1999.
Welcome, CPhill!
(4) Hint: Try to rearrange the equation, the first and second: Take -10y to the other side, and see what you can do.
@CPhill, 29 or -29? This was in step 2.
(2) Multiply the second equation by 2, so: -9x-14y=-29, 10x+7y=-2, -9x-14y=-29, 20x+14y=-4..
So, adding: y gets canceled, and 11x=-33, x=−3, so y= -9(-3)-14y=-29, 27-14y=-29, 14y=27+29, 14y=56, y=4.
Isn't the gap between two consecutive numbers, the same? So, 3x−x−1=12,2x−1=12,2x=32,x=34 .
We know that: 1a+1b=a∗b . If we multiply the denominator by b and a, respectively, we get: 1bab+1aba=a∗b . Suddenly, we go back to the problem, and it says: ab=25. So, we have:1a25+1b25=1a+1b25. We also know that a+b=13 , so 1a+1b25=a+b25=1325.
(a): 273+-22=273-22=251 Kelvin
(b): 273+0=273 Kelvin
(c): 273+-32=241 Kelvin
Plugging in the values, we get: −2−−4.1+5=−2+4.1+5=2.1+5=7.1.
Both negatives will make positive, so: −29+11=−18.
This is just: −14−10=−24.