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Thank you, CPhill! I have been working on them.

We just add all the red cars, which is $32+29+23=84.$ The total number of cars are $374.$ So, the answer is (D). 

I'm going to take you through three steps on how to solve this!

1. Quadratic Formula

The quadratic formula, $x = {-b \pm \sqrt{b^2-4ac} \over 2a}$ is a very neat formula on how to find the roots! Plugging the values into the equation, we yield $x_{1,\:2}=\frac{-\left(-10\right)\pm \sqrt{\left(-10\right)^2-4\cdot \:1\cdot \:25}}{2\cdot \:1}$ . Solving and doing all the calculations, we get $\frac{-\left(-10\right)}{2\cdot \:1}=\boxed{5}$, and that is our only solution!

2. Factoring

We can factor $x^2-10x+25=0$ into $\left(x-5\right)^2$ , after trying! Now, set $x-5=0$ , and our only solution is $\boxed{5}.$

3. Completing the Square

To complete the square, we first subtract $25$ from both sides, leaving us with $x^2-10x=-25$. Our goal is to write it in the form $x^2+2ax+a^2=\left(x+a\right)^2$ , so we solve for   $a$ , which is $-5.$ We add this to get   $x^2-10x+\left(-5\right)^2=-25+\left(-5\right)^2$ . Solving, we get , $\left(x-5\right)^2=0$

and our answer is $\boxed{x=5}$.

Too many steps! The answer is (B).

We can solve this using quadratic formula, $x = {-b \pm \sqrt{b^2-4ac} \over 2a}$ . (Glad that web2.0calc gives you this). Plugging the numbers into the quadratic formula, we have one solution as $x=\frac{-3+\sqrt{3^2-4\cdot \:1\left(-5\right)}}{2\cdot \:1}, \quad \frac{-3+\sqrt{29}}{2}$ and the other solution as $x=\frac{-3-\sqrt{3^2-4\cdot \:1\left(-5\right)}}{2\cdot \:1}:\quad \frac{-3-\sqrt{29}}{2}.$ Thus, the final solutions as $x=\frac{-3+\sqrt{29}}{2},\:x=\frac{-3-\sqrt{29}}{2}.$

There has to be! Maybe combinations!

Haha! Your explanation is still better! 

We first translate this into an equation:

$1*b^1+4*b^0+2*b^1+4*b^0=4*b^1+1*b^0$.

This is equal to $b+4+2b+4=4b+1$.

Solving we get, $3b+8=4b+1, b=7$.

Thus, the answer is base $\boxed{7}.$

No problem! Glad to help!

That's what I said. Just trying to list a few squares out, to find the answer.

Also, to cover the $361$ completely with the square root radical, $\sqrt{361}$ = \sqrt{361}