TonyDrummer2

Nevermind I found how

(ax-bx-ay+by ) / (x-y)

(x (a-b) -y (a-b) ) / (x-y)

((x - y ) ( a - b ) )/ (x-y)

a - b

Sorry double post, please answer on the more recent thread -___-

D**n but now I cannot find the other thread because it's been deleted...

I get what you're doing but how can I put this into maths:

Set both factors to 0 and the only solution to this that makes sense is that   a = 12   cm

Here are the solutions from the book:

One side is 9cm and the other 12cm.

Also, I think you forgot to square the hypotenuse when starting. That might be the problem...

Huge thanks for your help!

Only thing:

wouldn't it be 

2+sqrt3 "greater or equal to" x "lesser or equal to" 2-sqrt3

 2+sqrt3 <   x < 2-sqrt3

???

I am sorry.

I had this bug happening with 2 threads:

I post something, then it doesn't appear in my watchlist.

So I automatically assumed it wasn't posted at all and reposted.

I will be more careful I promise.

My bad, didn't picture it this way in my mind.

I already know this, don't know why I didn't think of it that way on this one...

Thanks!

Awesome!

Could you just explain to me how you go from:

sqrt (k + x ) = 7  - sqrt(x)   square both sides

to

k + x  =     49   -  14 sqrt(x) +  x  

I don't get how  ( - sqrt (x)  )^2  =  -14sqrt(x) + x

Here is the exact problem given in my class:

"Resolve in X":

sqrt (k + x) + sqrt (x) - 7 = 0

Now here is the answer provided by the book:

( k^2 - 98k + 2401 ) / 196    where k ∈ R