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1 + 1/ (1 βˆ’ 1 𝑖 )+ 𝑖 βˆ’3 (1 βˆ’ 𝑖)^5

 May 22, 2016
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  1 + 1/ (1 βˆ’ 1 𝑖 )+ 𝑖 βˆ’3 (1 βˆ’ 𝑖)^5=13.5 - 10.5i 

 May 22, 2016

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