1. (1’) The position function of a particle is given by s(t) = 3t2 − t3, t ≥ 0.

(a) When does the particle reach a velocity of 0 m/s? Explain the significance of this value of t.

(b) When does the particle have acceleration 0 m/s2?

Guest Dec 13, 2020

#1**0 **

Derivative of position fxn is velocity fxn

Derivtive of velocity fxn is acceleration function

v = 6t-3 this is zero when t = 1/2 sec this is the point the particle stops and reverses direction to positive displacement

a = 6 looks as thought the particle always has an acceleration of +6 it is never zero

Guest Dec 13, 2020