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1. (1’) The position function of a particle is given by s(t) = 3t2 − t3, t ≥ 0.
(a) When does the particle reach a velocity of 0 m/s? Explain the significance of this value of t.

(b) When does the particle have acceleration 0 m/s2?

 Dec 13, 2020
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Derivative of position fxn is velocity fxn

Derivtive of velocity fxn is acceleration function

 

v = 6t-3       this is zero when t = 1/2 sec     this is the point the particle stops and reverses direction to positive displacement

a = 6           looks as thought the particle always has an acceleration of +6    it is never zero

 Dec 13, 2020

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