Solve for x:
6+(-9-6 x)/3-x = 0
Put each term in 6+(-9-6 x)/3-x over the common denominator 3: 6+(-9-6 x)/3-x = 18/3+(-9-6 x)/3-(3 x)/3:
18/3+(-9-6 x)/3-(3 x)/3 = 0
18/3+(-9-6 x)/3-(3 x)/3 = (-3 x+(-9-6 x)+18)/3:
(-3 x-6 x-9+18)/3 = 0
Grouping like terms, -3 x-6 x-9+18 = (18-9)+(-6 x-3 x):
((18-9)+(-6 x-3 x))/3 = 0
-6 x-3 x = -9 x:
(-9 x+(18-9))/3 = 0
18-9 = 9:
(9-9 x)/3 = 0
Multiply both sides of (9-9 x)/3 = 0 by 3:
(3 (9-9 x))/3 = 3×0
(3 (9-9 x))/3 = 3/3×(9-9 x) = 9-9 x:
9-9 x = 3×0
0×3 = 0:
Answer: |
| 9-9x = 0 x=1
