Solve for d:
d/6+2/3 = (d-2)/4
Put each term in d/6+2/3 over the common denominator 6: d/6+2/3 = d/6+4/6:
d/6+4/6 = (d-2)/4
d/6+4/6 = (d+4)/6:
(d+4)/6 = (d-2)/4
Multiply both sides by 12:
(12 (d+4))/6 = (12 (d-2))/4
12/6 = (6×2)/6 = 2:
2 (d+4) = (12 (d-2))/4
12/4 = (4×3)/4 = 3:
2 (d+4) = 3 (d-2)
Expand out terms of the left hand side:
2 d+8 = 3 (d-2)
Expand out terms of the right hand side:
2 d+8 = 3 d-6
Subtract 3 d from both sides:
(2 d-3 d)+8 = (3 d-3 d)-6
2 d-3 d = -d:
-d+8 = (3 d-3 d)-6
3 d-3 d = 0:
8-d = -6
Subtract 8 from both sides:
(8-8)-d = -6-8
8-8 = 0:
-d = -6-8
-6-8 = -14:
-d = -14
Multiply both sides of -d = -14 by -1:
-d/(-1) = 14
(-1)/(-1) = 1:
Answer: |d = 14
