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1/(7+4*sqrt(3))+ 1/(7-4*sqrt(3))

 Sep 7, 2014

Best Answer 

 #2
avatar+129933 
+5

1/(7+4*sqrt(3))+ 1/(7-4*sqrt(3))   getting a common denominator, we have

[(7 - 4√3)  + (7 + 4√3)] / [ 49  - 16(3)] = 

14 / (49 - 48) =

14 / 1

14

 

 Sep 7, 2014
 #1
avatar+18 
0

Answer is 14.

you can aply (a+b)(a-b)=a^2-b^2 this formula on this math problem.

 Sep 7, 2014
 #2
avatar+129933 
+5
Best Answer

1/(7+4*sqrt(3))+ 1/(7-4*sqrt(3))   getting a common denominator, we have

[(7 - 4√3)  + (7 + 4√3)] / [ 49  - 16(3)] = 

14 / (49 - 48) =

14 / 1

14

 

CPhill Sep 7, 2014

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