1. AC is tangent to the circle with center at B.
The measure of ACB is 58dg.
What is the measure of ABC?
2. Chord AC intersects chord BD at point P in circle Z.
AP=4cm
BP=5cm
PC=8cm
What is PD?
1.
m∠BAC = 90º because AC is tangent to the circle with center at B.
m∠ACB = 58º
Every triangle has 180º.
m∠BAC + m∠ACB + m∠ABC = 180º
90º + 58º + m∠ABC = 180º
m∠ABC = 180º - 90º - 58º = 32º
2.
AP * PC = BP * PD
4 * 8 = 5 * PD
32 = 5 * PD
32/5 = PD
6.4 = PD
