1- An investment account offers an interest rate of 8% per annum compounded yearly.Assuming a single deposit £39700 is placed in this investment account.how long would it take for £39700 to amount to £ 68900 ,assuming that £100 is withdraw at the end of each of the first two years and thereafter no further withdrawals are made? 2-A man deposits £1000 every half year into a pension fund earning 6% interest annum ,compounded half yearly .Deposit are made at the start of each half year.How much will the fund be worth at the end of 7.5 years after the initial deposit?
2) 1000 pounds at the beginning of each half year
interest rate is 0.03 each half year
time period is 15 half years
Since payments are at the beginning of each period it is an annuity due
Since there is no money at the beginning and yourwant to know how much there is at the end it is a future value.
so
you need to use the future value of an annuity due formula with all the values I have given you.
Can you take it from there ? :)
1)
At the end of year 1 he will have 39700*1.08-100 = 42776.00
At the end of year 2 he will have 42776*1.08-100=46098.08
then
$$\\68900=49098.08(1+0.08)^n\\\\
68900/49098.08=(1.08)^n\\\\
log(68900/49098.08)=log(1.08)^n\\\\
log(68900/49098.08)=nlog(1.08)\\\\
\frac{log(68900/49098.08)}{log1.08}=n\\\\
n=\frac{log(68900/49098.08)}{log1.08}\\\\$$
$${\frac{{log}_{10}\left({\frac{{\mathtt{68\,900}}}{{\mathtt{49\,098.08}}}}\right)}{{log}_{10}\left({\mathtt{1.08}}\right)}} = {\mathtt{4.402\: \!698\: \!337\: \!383\: \!920\: \!9}}$$
round up to 5 because he doestn't get the interest until the end of the year.
2+5=7 years
2) 1000 pounds at the beginning of each half year
interest rate is 0.03 each half year
time period is 15 half years
Since payments are at the beginning of each period it is an annuity due
Since there is no money at the beginning and yourwant to know how much there is at the end it is a future value.
so
you need to use the future value of an annuity due formula with all the values I have given you.
Can you take it from there ? :)