(1)/(cot(x)) - (sec(x))/(csc(x)) = cos(x)
As written, this simplifies to :
[1/cot(x) ] - sec(x)/csc(x) =
tan(x) - sin(x) / cos(x) =
sin(x)/cos(x) - sin(x)/cos(x) =
0 = cos (x) ??????
(1)/(cot(x)) - (sec(x))/(csc(x)) = cos(x)
Am I supposed to prove this or what solve it?
\(\frac{1}{cot(x)} - \frac{sec(x)}{csc(x)}= cos(x)\\ \frac{sin(x)}{cos(x)} - \frac{sin(x)}{cos(x)}=cos(x)\\ 0=cos(x)\\ x= \frac{\pi}{2}+n\pi\qquad n\in Z\)
Same as CPhill found :)