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(1)/(cot(x)) - (sec(x))/(csc(x)) = cos(x)

 Dec 29, 2015

Best Answer 

 #2
avatar+118587 
+10

(1)/(cot(x)) - (sec(x))/(csc(x)) = cos(x)

 

Am I supposed to prove this or what solve it?

 

\(\frac{1}{cot(x)} - \frac{sec(x)}{csc(x)}= cos(x)\\ \frac{sin(x)}{cos(x)} - \frac{sin(x)}{cos(x)}=cos(x)\\ 0=cos(x)\\ x= \frac{\pi}{2}+n\pi\qquad n\in Z\)

 

 

Same as CPhill found :)

 Dec 29, 2015
 #1
avatar+128089 
+5

(1)/(cot(x)) - (sec(x))/(csc(x)) = cos(x)

 

As written, this simplifies to :

 

[1/cot(x) ] - sec(x)/csc(x)  =

 

tan(x) - sin(x) / cos(x)  =

 

sin(x)/cos(x) - sin(x)/cos(x) =

 

0  =   cos (x)         ??????

 

 

 

cool cool cool

 Dec 29, 2015
 #2
avatar+118587 
+10
Best Answer

(1)/(cot(x)) - (sec(x))/(csc(x)) = cos(x)

 

Am I supposed to prove this or what solve it?

 

\(\frac{1}{cot(x)} - \frac{sec(x)}{csc(x)}= cos(x)\\ \frac{sin(x)}{cos(x)} - \frac{sin(x)}{cos(x)}=cos(x)\\ 0=cos(x)\\ x= \frac{\pi}{2}+n\pi\qquad n\in Z\)

 

 

Same as CPhill found :)

Melody Dec 29, 2015

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