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$${\left({\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{\mathtt{j}}\right)}^{{\mathtt{n}}}{\mathtt{\,\small\textbf+\,}}{\left({\mathtt{1}}{\mathtt{\,\small\textbf+\,}}{{\mathtt{j}}}^{{\mathtt{2}}}\right)}^{{\mathtt{n}}}$$ could anyone help me 

 Jan 2, 2015

Best Answer 

 #1
avatar+33661 
+10

Depends what j is.  If it is √-1 (electrical engineers usually use j instead of i, as they use i for current) then it simplifies to (1 +j)n

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 Jan 3, 2015
 #1
avatar+33661 
+10
Best Answer

Depends what j is.  If it is √-1 (electrical engineers usually use j instead of i, as they use i for current) then it simplifies to (1 +j)n

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Alan Jan 3, 2015

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