(1-log(24, 6))*(1-log(24, 4))=? и решение

(1-log(24, 6))*(1-log(24, 4)) = 1.0000000000000005         

                                         by just plugging into the Web2.0 calculator....      ~~ 1

log(24, 6)  =  log₆24  =  log₆(6 · 4)  =  log₆6 + log₆4  =  1 + log₆4   

 

log(24, 4)  =  log₄24  =  log₄(4 · 6)  =  log₄4 + log₄6  =  1 + log₄6

 

[1 - log(24,6) ] · [1 - log(24, 4) ]  =  [ 1 - (1 + log₆4) ] · [ 1 - (1 + log₄6) ]

                                                   =  [ - log₆4 ] · [ - log₄6 ] 

                                                   =  log₆4 · log₄6

 

Changing these both into base 10:  =  [ log4 / log6 ] · [ log6 / log4 ]  =  1